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Finding the Inverse Laplace Transform of a Given Function

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Understanding the Problem

Today's challenge revolves around determining the inverse Laplace transform of a specific function. The task at hand is to uncover the inverse Laplace transform, denoted as L^(-1){F(s)}.

Finding the inverse Laplace transform of a function

Photo by Artur Aldyrkhanov on Unsplash

The Problem of the Day

This section is dedicated to providing problems and thorough solutions to enhance your understanding of mathematical methods.

The Approach to the Solution

Addressing this problem is akin to tackling integral calculations. Just as there are fundamental integrals that everyone should memorize, certain techniques—like integration by parts and substitution—are essential tools in your toolkit. When it comes to finding inverse Laplace transforms, the same principle applies; familiarity with a few basic transforms and techniques is crucial.

One vital transform to remember is:

Basic inverse Laplace transform to know

This transform stems from applying the Laplace shifting theorem to the constant function 1. If we instead consider:

Function for Laplace transform adjustment

we can manipulate the denominator to become real:

Real part of the denominator

Furthermore, due to the linearity of the Laplace transform, we can derive from Euler’s formula:

Euler's formula representation

By analyzing both the real and imaginary components, we find:

Real and imaginary part comparison

For the case when s=1, we have made notable advancements in determining our L^(-1){F(s)}:

Progress on inverse Laplace transform

Utilizing the Convolution Theorem

Next, we can leverage the well-known convolution theorem, which applies to both Fourier and Laplace transforms. This theorem states that for two functions, f(t) and g(t), with their corresponding Laplace transforms F(s) and G(s), the following identity holds true:

Convolution theorem identity

Here, the star symbol indicates the convolution operation:

Convolution operation definition

Thus, our task reduces to calculating the convolution of sin(t) with itself. Let's proceed with that:

Calculating convolution of sin(t)

To make progress, we should apply a trigonometric addition formula. I can't recall it off the top of my head, so let's derive it quickly:

Deriving trigonometric addition formula

By comparing the real and imaginary components, we arrive at:

Result from comparing components

Now, we can insert this into the integral:

Inserting into the integral

Both integrals can be evaluated using integration by parts:

First integral solution

and

Second integral solution

Compiling our findings yields:

Final result of the calculation

Conclusively, the inverse Laplace transform of:

Given function for inverse Laplace transform

is:

Result of the inverse Laplace transform

This video illustrates the Inverse Laplace Transform with examples and highlights key theorems vital for mastering the topic.

In this tutorial, learn how to compute the Inverse Laplace Transform of the function (s + 4)/(s^2 + 4s + 8), detailing step-by-step methods.

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